1/y^2+2y=15

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Solution for 1/y^2+2y=15 equation: 



1/y^2+2y=15

We move all terms to the left:

1/y^2+2y-(15)=0



Domain of the equation: y^2!=0

y^2!=0/

y^2!=√0

y!=0

y∈R



We add all the numbers together, and all the variables

2y+1/y^2-15=0

We multiply all the terms by the denominator


2y*y^2-15*y^2+1=0

We add all the numbers together, and all the variables

-15y^2+2y*y^2+1=0

Wy multiply elements

-15y^2+2y^3+1=0

We do not support eypression: y^3

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